Lewis acids are substances whose octet is incomplete and accept electrons. Boric acid is a monobasic weak acid. It does not liberate \(H ^{+}\) ion but instead accepts electrons from the \(OH ^{-}\) ion, i.e., it behaves as a Lewis acid.
The reaction of boric acid can be represented as:
\(H_3PO_3 + H_2O \rightarrow B(OH)_4^{-} + H^{+}\)
Alternatively, the following reaction can also be observed:
\(B(OH)_3 + 2H_2O \rightarrow [B(OH)_4]^{-} + H_3O^{+}\)
The structure of \(H_3BO_3\) is as shown below, where the octet of boron in \(H_3BO_3\) is incomplete. This incomplete octet allows boric acid to act as a Lewis acid, accepting electron pairs from other molecules.
Given below are two statements: One is labelled as Assertion (A) and the other is labelled as Reason (R).
Assertion (A): A typical unfertilized, angiosperm embryo sac at maturity is 8-nucleate and 7-celled.
Reason (R): The egg apparatus has 2 polar nuclei.
In the light of the above statements, choose the correct answer from the options given below: