Lewis acids are substances whose octet is incomplete and accept electrons. Boric acid is a monobasic weak acid. It does not liberate \(H ^{+}\) ion but instead accepts electrons from the \(OH ^{-}\) ion, i.e., it behaves as a Lewis acid.
The reaction of boric acid can be represented as:
\(H_3PO_3 + H_2O \rightarrow B(OH)_4^{-} + H^{+}\)
Alternatively, the following reaction can also be observed:
\(B(OH)_3 + 2H_2O \rightarrow [B(OH)_4]^{-} + H_3O^{+}\)
The structure of \(H_3BO_3\) is as shown below, where the octet of boron in \(H_3BO_3\) is incomplete. This incomplete octet allows boric acid to act as a Lewis acid, accepting electron pairs from other molecules.
Given below are two statements. 
In the light of the above statements, choose the correct answer from the options given below:
Given below are two statements:
Statement I: Nitrogen forms oxides with +1 to +5 oxidation states due to the formation of $\mathrm{p} \pi-\mathrm{p} \pi$ bond with oxygen.
Statement II: Nitrogen does not form halides with +5 oxidation state due to the absence of d-orbital in it.
In the light of the above statements, choose the correct answer from the options given below:
Given below are the pairs of group 13 elements showing their relation in terms of atomic radius. $(\mathrm{B}<\mathrm{Al}),(\mathrm{Al}<\mathrm{Ga}),(\mathrm{Ga}<\mathrm{In})$ and $(\mathrm{In}<\mathrm{Tl})$ Identify the elements present in the incorrect pair and in that pair find out the element (X) that has higher ionic radius $\left(\mathrm{M}^{3+}\right)$ than the other one. The atomic number of the element (X) is
