Step 1: Understanding the Concept:
This is a word problem involving percentages. We first need to calculate the sale price of a single DVD and then determine how many of them can be bought with a given amount of money.
Step 2: Detailed Explanation:
First, find the sale price of one DVD.
The regular price is \( d \) dollars.
The discount is 20% of the regular price.
\[ \text{Discount amount} = 20% \text{ of } d = 0.20 \times d = 0.2d \]
The sale price is the regular price minus the discount amount.
\[ \text{Sale Price} = d - 0.2d = 0.8d \]
We can also express this price as a fraction:
\[ 0.8d = \frac{8}{10}d = \frac{4}{5}d \]
Next, find how many DVDs can be purchased for \( x \) dollars.
The number of items that can be purchased is the total amount of money available divided by the price per item.
\[ \text{Number of DVDs} = \frac{\text{Total money}}{\text{Sale Price per DVD}} \]
\[ \text{Number of DVDs} = \frac{x}{\frac{4}{5}d} \]
To divide by a fraction, we multiply by its reciprocal.
\[ \text{Number of DVDs} = x \times \frac{5}{4d} = \frac{5x}{4d} \]
Step 3: Final Answer:
The number of DVDs that can be purchased is \(\frac{5x}{4d}\).
If \(8x + 5x + 2x + 4x = 114\), then, \(5x + 3 = ?\)
If \(r = 5 z\) then \(15 z = 3 y,\) then \(r =\)