To solve this problem, we need to determine the instantaneous power given the displacement function of a particle and the constant force applied.
Displacement Function: \( x(t) = 2t - 1 \)
Force: \( F = 5 \, \text{N} \)
1. Velocity Calculation: The instantaneous velocity \( v(t) \) is the derivative of the displacement function \( x(t) \) with respect to time \( t \).
\( v(t) = \frac{d}{dt}(2t - 1) = 2 \, \text{m/s} \)
2. Power Calculation: Instantaneous power \( P \) is given by the product of force and instantaneous velocity.
\( P = F \times v(t) \)
Substituting the given values:
\( P = 5 \, \text{N} \times 2 \, \text{m/s} = 10 \, \text{W} \)
Thus, the value of instantaneous power is 10 W.

Potential energy (V) versus distance (x) is given by the graph. Rank various regions as per the magnitudes of the force (F) acting on a particle from high to low. 
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