To solve this problem, we need to determine the instantaneous power given the displacement function of a particle and the constant force applied.
Displacement Function: \( x(t) = 2t - 1 \)
Force: \( F = 5 \, \text{N} \)
1. Velocity Calculation: The instantaneous velocity \( v(t) \) is the derivative of the displacement function \( x(t) \) with respect to time \( t \).
\( v(t) = \frac{d}{dt}(2t - 1) = 2 \, \text{m/s} \)
2. Power Calculation: Instantaneous power \( P \) is given by the product of force and instantaneous velocity.
\( P = F \times v(t) \)
Substituting the given values:
\( P = 5 \, \text{N} \times 2 \, \text{m/s} = 10 \, \text{W} \)
Thus, the value of instantaneous power is 10 W.
AB is a part of an electrical circuit (see figure). The potential difference \(V_A - V_B\), at the instant when current \(i = 2\) A and is increasing at a rate of 1 amp/second is: