Question:
At a given temperature and pressure, the equilibrium constant values for the equilibria are given below:
\[ 3A_2 + B_2 \rightleftharpoons 2A_3B, \, K_1 \]
\[ A_3B \rightleftharpoons \frac{3}{2}A_2 + \frac{1}{2}B_2, \, K_2 \]
The relation between \( K_1 \) and \( K_2 \) is:
At a given temperature and pressure, the equilibrium constant values for the equilibria are given below:
\[ 3A_2 + B_2 \rightleftharpoons 2A_3B, \, K_1 \]
\[ A_3B \rightleftharpoons \frac{3}{2}A_2 + \frac{1}{2}B_2, \, K_2 \]
The relation between \( K_1 \) and \( K_2 \) is:
\[ 3A_2 + B_2 \rightleftharpoons 2A_3B, \, K_1 \]
\[ A_3B \rightleftharpoons \frac{3}{2}A_2 + \frac{1}{2}B_2, \, K_2 \]
The relation between \( K_1 \) and \( K_2 \) is:
Updated On: Dec 9, 2024
- \( K_1^2 = 2K_2 \)
- \( K_2 = \frac{K_1}{2} \)
- \( K_1 = \frac{1}{\sqrt{K_2}} \)
- \( K_2 = \frac{1}{\sqrt{K_1}} \)
Hide Solution
Verified By Collegedunia
The Correct Option is D
Solution and Explanation
The second equilibrium reaction is the reverse of the first reaction divided by 2.
Therefore, the relationship between the equilibrium constants is:
\[K_{2}=\frac{1}{\sqrt{K_{1}}}\]
Was this answer helpful?
0
0
Top Questions on Law Of Chemical Equilibrium And Equilibrium Constant
- For the gas phase homogeneous equilibrium:
\[ 2X(g) \rightleftharpoons 2Y(g) + Z(g) \]
$K_C$ at 400K is $1 \times 10^{-3}$ mol L-1. What is the value of $K_P$ for the equilibrium at 400K?\[ R = 0.082 \, \text{L atm K}^{-1} \, \text{mol}^{-1} \]
- KEAM - 2024
- Chemistry
- Law Of Chemical Equilibrium And Equilibrium Constant
- A zero-order reaction is one whose rate is independent of:
- CBSE CLASS XII - 2024
- Chemistry
- Law Of Chemical Equilibrium And Equilibrium Constant
- For the reaction in equilibrium:
N2(g) + 3H2(g) ⇌ 2NH3(g), ΔH = -Q
Reaction is favoured in forward direction by:- NEET (UG) - 2024
- Chemistry
- Law Of Chemical Equilibrium And Equilibrium Constant
- At \(-20^\circ \text{C}\) and 1 atm pressure, a cylinder is filled with an equal number of \(H_2\), \(I_2\), and \(HI\) molecules for the reaction:
\[H_2(g) + I_2(g) \rightleftharpoons 2HI(g)\] The \(K_P\) for the process is \(x \times 10^{-1}\).
\(x = ___________)
Given: \(R = 0.082 \, \text{L atm K}^{-1} \text{mol}^{-1}\)- JEE Main - 2024
- Chemistry
- Law Of Chemical Equilibrium And Equilibrium Constant
- The equilibrium $\mathrm{Cr_2O_7^{2-}} \rightleftharpoons 2\mathrm{CrO_4^{2-}}$ is shifted to the right in:
- JEE Main - 2024
- Chemistry
- Law Of Chemical Equilibrium And Equilibrium Constant
View More Questions
Questions Asked in NEET exam
- In a uniform magnetic field of \(0.049 T\), a magnetic needle performs \(20\) complete oscillations in \(5\) seconds as shown. The moment of inertia of the needle is \(9.8 \times 10 kg m^2\). If the magnitude of magnetic moment of the needle is \(x \times 10^{-5} Am^2\); then the value of '\(x\)' is
- NEET (UG) - 2024
- Magnetic Field
- Given below are two statements:
Statement I: Mitochondria and chloroplasts both double membranes bound organelles.
Statement II: Inner membrane of mitochondria is relatively less permeable, as compared chloroplast. I
In the light of the above statements, choose the mis appropriate answer from the options given below- NEET (UG) - 2024
- Cell structure and organelles
- The highest number of helium atoms is in
- NEET (UG) - 2024
- Electronic configuration of atoms and ions
- A light ray enters through a right angled prism at point P with the angle of incidence 30° as shown in figure. It travels through the prism parallel to its base BC and emerges along the face AC. The refractive index of the prism is :
- NEET (UG) - 2024
- Refraction Through A Prism
- Given below are two statements: one is labelled as Assertion A and the other is labelled as Reason R.
Assertion A : The potential (V) at any axial point, at 2 m distance(r) from the centre of the dipole of dipole moment vector \(\vec{P}\) of magnitude, 4 × 10-6 C m, is ± 9 × 103 V.
(Take \(\frac{1}{4\pi\epsilon_0}=9\times10^9\) SI units)
Reason R : \(V=±\frac{2P}{4\pi \epsilon_0r^2}\), where r is the distance of any axial point, situated at 2 m from the centre of the dipole.
In the light of the above statements, choose the correct answer from the options given below :- NEET (UG) - 2024
- Magnetic Field
View More Questions