Question:
At 500 K, for a reversible reaction \(A_{2_{(g)}}+B_{2_{(g)}}⇌2AB_{(g)}\) in a closed container, KC = 2 × 10-5. In the presence of catalyst, the equilibrium is attaining 10 times faster. The equilibrium constant KC in the presence of catalyst at the same temperature is
At 500 K, for a reversible reaction \(A_{2_{(g)}}+B_{2_{(g)}}⇌2AB_{(g)}\) in a closed container, KC = 2 × 10-5. In the presence of catalyst, the equilibrium is attaining 10 times faster. The equilibrium constant KC in the presence of catalyst at the same temperature is
Updated On: Nov 8, 2024
- 2 × 10-4
- 2 × 10-6
- 2 × 10-10
- 2 × 10-5
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The Correct Option is D
Solution and Explanation
The correct answer is (D) : 2 × 10-5.
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