Question:

Assuming the earth to be a sphere of uniform density, the acceleration due to gravity inside the earth at a distance of $r$ from the centre is proportional to

Updated On: Jul 28, 2022
  • $r$
  • $r^{-1}$
  • $r^2$
  • $r^{-2}$
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The Correct Option is A

Solution and Explanation

Acceleration due to gravity at depth d from the surface of the earth or at a distance r from the centre ????of the earth $g' = \frac{4}{3}\pi\rho Gr$ Hence $g??propto r$
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Concepts Used:

Gravitation

In mechanics, the universal force of attraction acting between all matter is known as Gravity, also called gravitation, . It is the weakest known force in nature.

Newton’s Law of Gravitation

According to Newton’s law of gravitation, “Every particle in the universe attracts every other particle with a force whose magnitude is,

  • F ∝ (M1M2) . . . . (1)
  • (F ∝ 1/r2) . . . . (2)

On combining equations (1) and (2) we get,

F ∝ M1M2/r2

F = G × [M1M2]/r2 . . . . (7)

Or, f(r) = GM1M2/r2

The dimension formula of G is [M-1L3T-2].