Question:

Assume that a ship has length \(L = 200 \, \text{m}\) and operates at a design speed \(U = 12 \, \text{m/s}\). If in a turning circle maneuver the ship exhibits a steady turning diameter of \(6L\), then the yaw rate of the ship is ________________ rad/s (correct to two decimal places).

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Yaw rate in steady turning motion equals ship speed divided by turning radius. Larger turning diameters result in lower yaw rates.
Updated On: Dec 2, 2025
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Correct Answer: 0.02

Solution and Explanation

Turning diameter: \[ D = 6L = 6 \times 200 = 1200\ \text{m} \] Turning radius: \[ R = \frac{D}{2} = 600\ \text{m} \] Yaw rate (\(\dot{\psi}\)): \[ \dot{\psi} = \frac{U}{R} = \frac{12}{600} = 0.02\ \text{rad/s} \]
Final Answer: 0.02–0.02 rad/s
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