{"@context":"https://schema.org/","@type":"Quiz","dateCreated":"2024-07-10T12:27:23.300Z","dateModified":"2024-07-15T11:30:07.087Z","typicalAgeRange":"11-18","educationalLevel":"GPAT","assesses":"Pharmaceutics - Packaging Materials","educationalAlignment":[{"@type":"AlignmentObject","alignmentType":"educationalTopic","targetName":"Packaging Materials"},{"@type":"AlignmentObject","alignmentType":"educationalSubject","targetName":"Pharmaceutics"},{"@type":"AlignmentObject","alignmentType":"educationalExam","targetName":"GPAT"}],"name":"Quiz about Packaging Materials","about":{"@type":"Thing","name":"Pharmaceutics - Packaging Materials"},"hasPart":[{"@type":"Question","eduQuestionType":"Multiple choice","learningResourceType":"Practice problem","educationalLevel":"intermediate","name":"Question About Packaging Materials","text":"As per USP, test limit for treated soda lime glass with container size of 200 ml is:-","encodingFormat":"text/markdown","comment":{"@type":"Comment","text":"\"\""},"suggestedAnswer":[{"@type":"Answer","position":0,"encodingFormat":"text/markdown","text":"

0.70ml of 0.02N Acid

","comment":{"@type":"Comment","text":"\"\""}},{"@type":"Answer","position":1,"encodingFormat":"text/markdown","text":"

1.0ml of 0.2N Acid

","comment":{"@type":"Comment","text":"\"\""}},{"@type":"Answer","position":2,"encodingFormat":"text/markdown","text":"

0.20ml of 0.02N Acid

","comment":{"@type":"Comment","text":"\"\""}},{"@type":"Answer","position":3,"encodingFormat":"text/markdown","text":"

0.70ml of 0.2N Acid

","comment":{"@type":"Comment","text":"\"\""}}],"acceptedAnswer":{"@type":"Answer","position":2,"encodingFormat":"text/markdown","text":"

0.20ml of 0.02N Acid

","answerExplanation":{"@type":"text","text":"The correct answer is option (C) : 0.20ml of 0.02N Acid"},"comment":{"@type":"Comment","text":"\"\""}}}]}

As per USP, test limit for treated soda lime glass with container size of 200 ml is:-

The Correct Option is C

Solution and Explanation

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