Question

Considering away matches only, which of the following teams is the second ranking team?

• A. AS
• B. CH
• C. WG
• D. SW
• E. WB
• A. 2
• B. 3
• C. 4
• D. 5
• J. 6
• A. AS
• B. WB
• C. WH
• D. MC
• O. SW
• A. 5
• B. 6
• C. \(\geq 6\)
• D. \(\geq 6 \text{ and } \leq 13\)
• T. \(\geq 6 \text{ and } \leq 14\)

Answer 1

The Correct Option is D

Step 1: Points are awarded \(3\) for a win and \(1\) for a draw. For away-only ranking we compute \[ \text{Away Points}=\text{Overall Points}-\text{Home Points}. \] From Table~1 (overall) and Table~2 (home): AS: Overall \(W=1,D=1⇒ 4\) pts; Home \(D=1⇒ 1\) pt \(⇒\) Away \(=3\).
CH: Overall \(W=3⇒ 9\) pts; Home \(W=2⇒ 6\) pts \(⇒\) Away \(=3\).
WG: Overall \(W=1,D=1⇒ 4\) pts; Home (not listed \(⇒ 0\) pts) \(⇒\) Away \(=4\).
SW: Overall \(W=2,D=1⇒ 7\) pts; Home \(W=1,D=1⇒ 4\) pts \(⇒\) Away \(=3\).
WB: Overall \(7\) pts; Home \(6\) pts \(⇒\) Away \(=1\).
Step 2: Highest away points is WG with \(4\) pts. The next highest (second) are AS, CH and SW with \(3\) pts each. Apply the tie-breaker: Goal Difference (GD) on away matches.
From Chart~1 (overall GD) and Table~2 (home GD \(=\) GF\(-\)GA):
\[ \text{Away GD}=\text{Overall GD}-\text{Home GD}. \] SW: \(8-3=5\), AS: \(2-1=1\), CH: \(6-6=0\).
So among the \(3\)-point teams, SW has the best away GD.
Step 3: Therefore, the second ranking team on away matches is \(\boxed{\text{SW}}\).

Answer 2

Step 1: Calculate away points \(=\) Overall points – Home points. Using Tables 1 and 2:
CH: 9–6 = 3
SW: 7–4 = 3
MC: 7–6 = 1
MU: 6–3 = 3
WH: 4–6 = –2 (not possible, must be 0)
EV: 4–1 = 3
AS: 4–1 = 3
WG: 4–0 = 4
NC: 4–3 = 1
FU: 3–1 = 2
ST: 3–0 = 3
SU: 2–0 = 2
WB: 7–6 = 1
Step 2: Teams with 0 or 1 away point are: MC, WH, NC, WB (and FU possibly adjusted). Counting carefully, at least 5 teams fall into this category.
Hence, the least number is \(\boxed{5}\).

Answer 3

Step 1: Rank the teams by home points and away points separately.
Step 2: Compute \(\text{pos} = \text{home rank} - \text{away rank}\). A high positive pos means the team performs much better in away matches compared to home.
Step 3: From the data, AS has poor home record (low home rank), but relatively good away performance (higher away rank). This maximizes the difference.
Thus, \(\boxed{\text{AS}}\) has the maximum pos value.

Answer 4

Step 1: Compute Away GD = Overall GD – Home GD (from Chart 1 and Table 2).
Step 2: List all Away GD values and identify distinct numbers.
Step 3: After calculation, the set of unique values has 6 distinct elements.
Therefore, the answer is \(\boxed{6}\).