Aniline (C6H5NH2) is a primary amine and exhibits certain reactivity patterns due to the presence of the amine group (-NH2), which is an electron-donating group. The electron-donating nature of the amine group makes the aromatic ring more reactive towards electrophilic substitution reactions. However, the amine group also affects its reactivity with certain reagents.
Option A: Friedel-Crafts reaction, as aniline does not undergo Friedel-Crafts reactions due to deactivation of the catalyst by the amine group.
Aniline (C₆H₅NH₂) is an aromatic amine, and its amino group (-NH₂) is an electron-donating group. This makes the ring more reactive towards electrophilic substitution reactions such as nitration, sulphonation, and bromination. However, the amino group also strongly deactivates the ring towards Friedel-Craft reactions (both alkylation and acylation) due to the strong electron-donating nature of the -NH₂ group.
Therefore, aniline does not undergo Friedel-Craft reactions. It can, however, undergo nitration, sulphonation, and bromination.
Hence, the correct answer is (C): Friedel-Craft reaction.
Given below are two statements:
Statement I: All the pairs of molecules \((\mathrm{PbO}, \mathrm{PbO_2}); (\mathrm{SnO}, \mathrm{SnO_2})\) and \((\mathrm{GeO}, \mathrm{GeO_2})\) contain amphoteric oxides.
Statement II: \(\mathrm{AlCl_3}, \mathrm{BH_3}, \mathrm{BeH_2}\) and \(\mathrm{NO_2}\) all have incomplete octet.
In the light of the above statements, choose the correct option.
Match the following:
In the following, \( [x] \) denotes the greatest integer less than or equal to \( x \). 
Choose the correct answer from the options given below:
For x < 0:
f(x) = ex + ax
For x ≥ 0:
f(x) = b(x - 1)2