Aniline (C6H5NH2) is a primary amine and exhibits certain reactivity patterns due to the presence of the amine group (-NH2), which is an electron-donating group. The electron-donating nature of the amine group makes the aromatic ring more reactive towards electrophilic substitution reactions. However, the amine group also affects its reactivity with certain reagents.
Option A: Friedel-Crafts reaction, as aniline does not undergo Friedel-Crafts reactions due to deactivation of the catalyst by the amine group.
Aniline (C₆H₅NH₂) is an aromatic amine, and its amino group (-NH₂) is an electron-donating group. This makes the ring more reactive towards electrophilic substitution reactions such as nitration, sulphonation, and bromination. However, the amino group also strongly deactivates the ring towards Friedel-Craft reactions (both alkylation and acylation) due to the strong electron-donating nature of the -NH₂ group.
Therefore, aniline does not undergo Friedel-Craft reactions. It can, however, undergo nitration, sulphonation, and bromination.
Hence, the correct answer is (C): Friedel-Craft reaction.
Consider the following reaction:
\[ A + NaCl + H_2SO_4 \xrightarrow[\text{Little amount}]{} CrO_2Cl_2 + \text{Side products} \] \[ CrO_2Cl_2(\text{Vapour}) + NaOH \rightarrow B + NaCl + H_2O \] \[ B + H^+ \rightarrow C + H_2O \]
The number of terminal 'O' present in the compound 'C' is ________.
In a practical examination, the following pedigree chart was given as a spotter for identification. The students identify the given pedigree chart as 