When unpolarized light is incident on a surface at Brewster's angle (\(i_B\)), the reflected light is completely polarized perpendicular to the plane of incidence. Brewster's angle is given by the relation:
\[
\tan i_B = \mu
\]
where \( \mu \) is the refractive index of the medium.
Given \( \mu = 1.73 \approx \sqrt{3} \), we have:
\[
\tan i_B = \sqrt{3} \implies i_B = 60^\circ
\]
The angle of incidence at Brewster's angle is \( 60^\circ \).
According to the law of reflection, the angle of reflection \( r \) is equal to the angle of incidence:
\[
\text{Angle of reflection} = i_B = 60^\circ
\]
At Brewster's angle, the reflected light is completely polarized.
The transmitted light is partially polarized.
The angle of refraction \( r' \) can be found using Snell's Law:
\[
\mu_1 \sin i_B = \mu_2 \sin r'
\]
Here, \( \mu_1 = 1 \) (air) and \( \mu_2 = 1.73 \):
\[
1 \times \sin 60^\circ = 1.73 \times \sin r'
\]
\[
\frac{\sqrt{3}}{2} = \sqrt{3} \cdot \sin r'
\]
\[
\sin r' = \frac{1}{2} \implies r' = 30^\circ
\]
So, at Brewster's angle of \( 60^\circ \), the reflected light is completely polarized, and the angle of reflection is \( 60^\circ \), while the angle of refraction is \( 30^\circ \).