\(Mg' = Mg \frac{R^2}{(R+h)^2}\)
\(Mg' = Mg \frac{R^2}{(R+2R)^2} = \frac{Mg}{9}\)
\(Mg' = Mg \frac{R^2}{(R+\frac{3}{2}R)^2} = \frac{Mg}{25}\)
\(Mg \left( \frac{4}{25} - \frac{1}{9} \right) = 49 \, \text{N}\)
A small point of mass \(m\) is placed at a distance \(2R\) from the center \(O\) of a big uniform solid sphere of mass \(M\) and radius \(R\). The gravitational force on \(m\) due to \(M\) is \(F_1\). A spherical part of radius \(R/3\) is removed from the big sphere as shown in the figure, and the gravitational force on \(m\) due to the remaining part of \(M\) is found to be \(F_2\). The value of the ratio \( F_1 : F_2 \) is:
The height from Earth's surface at which acceleration due to gravity becomes \(\frac{g}{4}\) is \(\_\_\)? (Where \(g\) is the acceleration due to gravity on the surface of the Earth and \(R\) is the radius of the Earth.)
The following diagram shown restriction sites in E. coli cloning vector pBR322. Find the role of ‘X’ and ‘Y’gens :