Question:

An object of mass 100 kg falls from point A to B as shown in figure. The change in its weight, corrected to the nearest integer is ($R_E$ is the radius of the earth):
Sol Figure

Updated On: Feb 19, 2025
  • 49 N
  • 89 N
  • 5 N
  • 10 N
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The Correct Option is A

Solution and Explanation

\(Mg' = Mg \frac{R^2}{(R+h)^2}\)

\(Mg' = Mg \frac{R^2}{(R+2R)^2} = \frac{Mg}{9}\)

\(Mg' = Mg \frac{R^2}{(R+\frac{3}{2}R)^2} = \frac{Mg}{25}\)

\(Mg \left( \frac{4}{25} - \frac{1}{9} \right) = 49 \, \text{N}\)

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