Question:

An object of density \( \rho \) is floating in a liquid with 75% of its volume submerged. The density of the liquid is:

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For floating bodies, the fraction of volume submerged equals the ratio of object’s density to the liquid’s density.
Updated On: Dec 6, 2025
  • \( \frac{4}{3}\rho \)
  • \( \frac{3}{2}\rho \)
  • \( \frac{8}{5}\rho \)
  • \( 2\rho \)
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The Correct Option is A

Solution and Explanation

Step 1: Use the principle of flotation.
A floating object displaces liquid whose weight equals its own: \[ \rho_{\text{object}} V g = \rho_{\text{liquid}} V_{\text{sub}} g. \] Step 2: Simplify the relation.
\[ \frac{\rho_{\text{object}}}{\rho_{\text{liquid}}} = \frac{V_{\text{sub}}}{V}. \] Given \( \frac{V_{\text{sub}}}{V} = 0.75 \), we get \[ \rho_{\text{liquid}} = \frac{\rho}{0.75} = \frac{4}{3}\rho. \]
Step 3: Final Answer.
Density of the liquid is \( \frac{4}{3}\rho. \)
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