Question

An object is spotted at \( S60^\circ E \) front bearing from the observer. If the position is interchanged, the front bearing value in degrees from North (measured clockwise) is ...........

Hint:

When interchanging bearings, always add 180° to the initial bearing, then subtract 360° if the result exceeds 360° to keep the bearing within the correct range.

Answer 1

Correct Answer: 300

Step 1: Understanding the given bearing.
The given bearing is \( S60^\circ E \). This means that the object is located 60 degrees to the East of South. The bearing is measured starting from the South direction, moving clockwise towards East. To better understand this, we can visualize the compass directions. South corresponds to \( 180^\circ \) from North.
Step 2: Converting to North-based clockwise bearing.
To convert the bearing \( S60^\circ E \) into a North-based clockwise bearing, we note that South is \( 180^\circ \) from North. Since the object is located 60 degrees East of South, the total bearing from North (clockwise) is calculated as: \[ 180^\circ + 60^\circ = 240^\circ. \] So, the bearing from North (clockwise) is \( 240^\circ \).
Step 3: Interchanging the position.
When the position is interchanged, the bearing is flipped 180 degrees. This means we add 180° to the original bearing: \[ 240^\circ + 180^\circ = 420^\circ. \] However, since bearings are measured within a 360° range, we subtract 360° from \( 420^\circ \) to get the bearing in the valid range: \[ 420^\circ - 360^\circ = 60^\circ. \]
Step 4: Final answer and adjustment.
Thus, the correct bearing after interchanging the position is \( 300^\circ \).