1. Initial Potential Energy: Initial potential energy (PE) = mgh, where m is the mass, g is acceleration due to gravity, and h is the initial height (10 m).
2. Kinetic Energy Just Before Impact: By conservation of energy, the potential energy is converted to kinetic energy (KE) just before the object strikes the ground: KE = mgh.
3. Kinetic Energy After Impact: The object loses 50% of its KE after striking the ground, so the remaining KE is 0.5(mgh).
4. Rebound Height: The remaining KE is converted back to potential energy as the object rebounds. Let h’ be the rebound height. 0.5(mgh) = mgh’ h’ = 0.5h = 0.5(10 m) = 5 m
5. Conclusion: The rebound height is 5 m.
For obtaining wattless current,……. is connected with AC supply.}
An inductor of 50.0 mH is connected to a source of 220 V. Then the rms current in the circuit will be ……. . The frequency of the source is 50 Hz.
A short bar magnet placed with its axis at \( 30^\circ \) and a uniform external magnetic field of 0.5 T experiences a torque of magnitude equal to \( 4.5 \times 10^{-2} \) J. Then the magnitude of the magnetic moment of the magnet will be