Let the marked price be \(MP\) and the cost price be \(CP\). The selling price (SP) is ₹504.
The discount is 20%, so the selling price is 80% of the marked price: \(0.8 \times MP = 504\). Therefore, \(MP = \frac{504}{0.8} = 630\).
There is a 5% profit, so the selling price is 105% of the cost price: \(1.05 \times CP = 504\). Therefore, \(CP = \frac{504}{1.05} = 480\).
The difference between the marked price and the cost price is \(MP - CP = 630 - 480 = 150\).
Let the cost price be $x$.
The selling price is $x + 0.05x = 1.05x$.
The marked price after a 20% discount is $504 = 0.8 \times \text{Marked Price}$.
Solving for $x$ gives the cost price as 150.
A furniture trader deals in tables and chairs. He has Rs. 75,000 to invest and a space to store at most 60 items. A table costs him Rs. 1,500 and a chair costs him Rs. 1,000. The trader earns a profit of Rs. 400 and Rs. 250 on a table and chair, respectively. Assuming that he can sell all the items that he can buy, which of the following is/are true for the above problem:
(A) Let the trader buy \( x \) tables and \( y \) chairs. Let \( Z \) denote the total profit. Thus, the mathematical formulation of the given problem is:
\[ Z = 400x + 250y, \]
subject to constraints:
\[ x + y \leq 60, \quad 3x + 2y \leq 150, \quad x \geq 0, \quad y \geq 0. \]
(B) The corner points of the feasible region are (0, 0), (50, 0), (30, 30), and (0, 60).
(C) Maximum profit is Rs. 19,500 when trader purchases 60 chairs only.
(D) Maximum profit is Rs. 20,000 when trader purchases 50 tables only.
Choose the correct answer from the options given below: