Step 1: Understanding the Power-Flow Rate Relationship
- Power \( P \) required to maintain the flow of an incompressible fluid is given by:
\[
P \propto Q^3
\]
where \( Q \) is the volumetric flow rate.
Step 2: Effect of Doubling Flow Rate
- If the flow rate is doubled:
\[
Q' = 2Q
\]
- New power required:
\[
P' = (2Q)^3 = 8P
\]
Step 3: Increase in Power
\[
\text{Increase in power} = P' - P = 8P - P = 7P
\]
\[
\text{Percentage increase} = \frac{7P}{P} \times 100 = 700%
\]
Step 4: Conclusion
Since the power increase is 700%, Option (3) is correct.