Question:

An engine pumps water continuously through a hose. If the speed with which the water passes through the hose nozzle is \( v \), and if \( k \) is the mass per unit length of the water jet as it leaves the nozzle, what is the rate at which kinetic energy is being imparted to the water?

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To find the rate of energy imparted to a moving fluid, use the formula for kinetic energy and multiply by the velocity of the fluid.
Updated On: Mar 25, 2025
  • \( 2kv^2 \)
  • \( 2kv^3 \)
  • \( 2kv^4 \)
  • None
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The Correct Option is A

Solution and Explanation

The kinetic energy imparted to the water per unit time is given by: \[ P = \frac{1}{2} k v^2 \cdot v = \frac{1}{2} k v^3 \] Thus, the rate at which kinetic energy is being imparted to the water is \( 2kv^3 \).
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