Question

An electron moves at right angle to a magnetic field of \( 5 \times 10^{-2} \, T \) with a speed of \( 6 \times 10^{7} \, \text{m/s} \). If the specific charge of the electron is \( 1.7 \times 10^{11} \, \text{C/kg} \), the radius of the circular path will be?

• A. 2.9 cm
• B. 3.9 cm
• C. 2.35 cm
• D. 2 cm

Hint:

The radius of the electron's circular path depends on its speed, charge, and the strength of the magnetic field.

Answer 1

The Correct Option is C

The radius of the circular path followed by an electron in a magnetic field can be calculated using the formula: \[ r = \frac{mv}{qB} \] Where \( m \) is the mass, \( v \) is the speed, \( q \) is the charge, and \( B \) is the magnetic field strength.