Question

An electromagnetic wave going through vacuum is described by \( E = E_0 \sin(kx - \omega t) \), \( B = B_0 \sin(kx - \omega t) \), then:

• A. \( E_0 k = B_0 \omega \)
• B. \( E_0 \omega = B_0 k \)
• C. \( E_0 B_0 = ok \)
• D. \( \frac{E_0}{B_0} = \frac{\omega}{k} \)

Hint:

For any electromagnetic wave traveling through vacuum, the ratio of the electric field amplitude to the magnetic field amplitude is equal to the ratio of angular frequency to the wave number.

Answer 1

The Correct Option is D

For an electromagnetic wave traveling in vacuum, the electric field (\(E\)) and magnetic field (\(B\)) are perpendicular to each other and to the direction of wave propagation. The relationship between the electric and magnetic fields is given by the equation: \[ \frac{E_0}{B_0} = \frac{\omega}{k} \] This relationship holds true for an electromagnetic wave traveling through vacuum.