Question:

An electric motor operates on a $50\, V$ supply and a current of $12\, A$. If the efficiency of the motor is $30\%$, what is the resistance of the winding of the motor?

Updated On: Jul 12, 2022
  • $ 6\,\Omega $
  • $ 4\,\Omega $
  • $ 2.9\,\Omega $
  • $ 3.1\,\Omega $
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The Correct Option is C

Solution and Explanation

$I=\frac{E-e}{R}$ ...(i) and $\eta \times 100=\left(\frac{e}{E}\right) \times 100$ ...(ii) $\therefore 30=\frac{e}{50} \times 100$ [from Eqs.(ii)] $\Rightarrow R=15\, V$ Thus, $R=\frac{50-15}{12}=2.9\, \Omega$
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Concepts Used:

Electromagnetic Induction

Electromagnetic Induction is a current produced by the voltage production due to a changing magnetic field. This happens in one of the two conditions:-

  1. When we place the conductor in a changing magnetic field.
  2. When the conductor constantly moves in a stationary field.

Formula:

The electromagnetic induction is mathematically represented as:-

e=N × d∅.dt

Where

  • e = induced voltage
  • N = number of turns in the coil
  • Φ = Magnetic flux (This is the amount of magnetic field present on the surface)
  • t = time

Applications of Electromagnetic Induction

  1. Electromagnetic induction in AC generator
  2. Electrical Transformers
  3. Magnetic Flow Meter