Step 1: Understanding the Concept:
Point \(A\) is the peak (vertex) of the parabolic arch. For a quadratic polynomial \(ax^{2} + bx + c\), the \(x\)-coordinate of the vertex is given by \(x = -b/(2a)\).
Step 2: Detailed Explanation:
The polynomial is \(p(x) = -0.0025x^{2} - 0.025x + 136\).
Comparing with \(ax^{2} + bx + c\):
\(a = -0.0025\), \(b = -0.025\), \(c = 136\).
Find the \(x\)-coordinate:
\[ x = \frac{-(-0.025)}{2 \times (-0.0025)} = \frac{0.025}{-0.005} = -5 \]
Now, find the \(y\)-coordinate by substituting \(x = -5\) into \(p(x)\):
\[ p(-5) = -0.0025(-5)^{2} - 0.025(-5) + 136 \]
\[ p(-5) = -0.0025(25) + 0.125 + 136 \]
\[ p(-5) = -0.0625 + 0.125 + 136 = 136.0625 \]
Step 3: Final Answer:
The co-ordinates of point \(A\) are \((-5, 136.0625)\).