During the electrolysis of an aqueous CuSO4 solution, copper metal is deposited at the cathode. This is because the copper ions (Cu\(^{2+}\)) are reduced to copper metal (Cu) at the cathode. The half-reaction at the cathode is:
\[
Cu^{2+} + 2e^- \rightarrow Cu
\]
At the anode, oxygen gas is evolved, but the question asks about the cathode, where copper is deposited. Hence, option (A) is the correct answer.