An analog signal is sampled at 100 MHz to generate 1024 samples. Only these samples are used to evaluate 1024-point FFT. The separation between adjacent frequency points (\( \Delta F \)) in FFT is \(\underline{\hspace{2cm}}\) kHz.
Show Hint
- 102.16
- 97.66
- 100.00
- 95.63
The Correct Option is B
Solution and Explanation
For this problem: \[ F_s = 100 \, \text{MHz}, N = 1024. \] Thus, \[ \Delta F = \frac{100 \, \text{MHz}}{1024} = 97.65625 \, \text{kHz}. \] The closest value to this is 97.66 kHz.
Final Answer: 97.66 kHz
Questions Asked in GATE BM exam
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- GATE BM - 2025
- General Physiology