Question:

Among $K^+, Li^+, Rb^+, Cs^+$, the number of cation(s) having ionic radii more than $Na^+$ is/are _____.

Updated On: Nov 18, 2025
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Correct Answer: 3

Solution and Explanation

To determine how many of the cations $K^+$, $Li^+$, $Rb^+$, and $Cs^+$ have ionic radii more than $Na^+$, we need to consider their ionic radii. The ionic radii (in pm) for these ions are approximately as follows: 

CationIonic Radius (pm)
$Li^+$76
$Na^+$102
$K^+$138
$Rb^+$152
$Cs^+$167

Comparing each cation to $Na^+$ (102 pm):

  • $Li^+$ (76 pm) < $Na^+$
  • $K^+$ (138 pm) > $Na^+$
  • $Rb^+$ (152 pm) > $Na^+$
  • $Cs^+$ (167 pm) > $Na^+$

Thus, the number of cations with ionic radii more than $Na^+$ is 3. This value fits within the expected range of 3,3, confirming its correctness.

Therefore, the answer is: 3

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