Question:

Ammonia is used in detection of $Cu^{2+}$ ion because

Updated On: Jul 6, 2022

aqueous solution of $NH_3$ reacts with $Cu^{2+}$ ion to form deep blue coloured complex
$NH_3$ reacts with $Cu^{2+}$ ion to give blue precipitate of $CuO$
aqueous solution of $NH_3$ reacts with $Cu^{2+}$ to form white coloured complex
$NH_3$ reacts with $Cu^{2+}$ ion to give green precipitate

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The Correct Option is A

$ {Cu^{2+}_{(aq)} +4NH3_{(aq)} ->}$ $\underset{\text{Deep blue}}{ {[Cu(NH3)4]^{2+}_{(aq)}}}$

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P block elements are those in which the last electron enters any of the three p-orbitals of their respective shells. Since a p-subshell has three degenerate p-orbitals each of which can accommodate two electrons, therefore in all there are six groups of p-block elements.
P block elements are shiny and usually a good conductor of electricity and heat as they have a tendency to lose an electron. You will find some amazing properties of elements in a P-block element like gallium. It’s a metal that can melt in the palm of your hand. Silicon is also one of the most important metalloids of the p-block group as it is an important component of glass.