Question:

Aluminium reacts with NaOH and forms compound 'X'. If the coordination number of aluminium in 'X' is 6, the correct formula of X is

Updated On: Jun 3, 2024
  • $[Al(H_2O)_4(OH)_2]^+$
  • $[Al(H_2O)_3(OH)_3]$
  • $[Al(H_2O)_2(OH)_4]^-$
  • $[Al(H_2O)_6](OH)_3$
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The Correct Option is C

Solution and Explanation

$2Al + 2NaOH + 2H_2O \longrightarrow ^{2NaAlO_3}_{Sodium\ \\ meta\ \\ aluminate}+3H_2$
Sodium meta alurninate, thus formed, is soluble in water and changes into the complex $[Al(H_2O)_2(OH)_4]^- $in which coordination number of Al is 6.
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Concepts Used:

Coordination Compounds

A coordination compound holds a central metal atom or ion surrounded by various oppositely charged ions or neutral molecules. These molecules or ions are re-bonded to the metal atom or ion by a coordinate bond.

Coordination entity:

A coordination entity composes of a central metal atom or ion bonded to a fixed number of ions or molecules.

Ligands:

A molecule, ion, or group which is bonded to the metal atom or ion in a complex or coordination compound by a coordinate bond is commonly called a ligand. It may be either neutral, positively, or negatively charged.