Question:

Alkyl cyanides undergo Stephen reduction to produce

Show Hint

Stephen reduction: \(R-CN \rightarrow R-CHO\) (nitrile to aldehyde) using \(SnCl_2/HCl\) followed by hydrolysis.
Updated On: Jan 5, 2026
  • aldehyde
  • secondary amine
  • primary amine
  • amide
Hide Solution
collegedunia
Verified By Collegedunia

The Correct Option is A

Solution and Explanation

Step 1: Recall Stephen reduction.
Stephen reduction is the partial reduction of nitriles (\(R-CN\)) using \(\text{SnCl}_2/HCl\).
Step 2: Intermediate formation.
Nitrile is reduced to iminium salt:
\[ R-CN \xrightarrow{SnCl_2/HCl} R-CH=NH\cdot HCl \]
Step 3: Hydrolysis gives aldehyde.
On hydrolysis:
\[ R-CH=NH \xrightarrow{H_2O} R-CHO \]
Step 4: Conclusion.
Hence alkyl cyanides give aldehydes in Stephen reduction.
Final Answer:
\[ \boxed{\text{(A) aldehyde}} \]
Was this answer helpful?
0
0