1. Each basidium undergoes one nuclear fusion (karyogamy) to form a diploid nucleus — so number of nuclear fusions equals number of basidia. For 60 basidia: nuclear fusions = 60.
2. Each basidium then undergoes one meiotic division (meiosis I and II sequence considered as one meiotic event) producing four haploid nuclei which form four basidiospores. Thus meiotic divisions per basidium = 1, total meiotic divisions = 60.
3. Each basidium produces 4 basidiospores, so total basidiospores = 60 \(\times\) 4 = 240.
4. Therefore the counts are 60 nuclear fusions; 60 meiotic divisions; 240 basidiospores — (1) 60; 60 & 240.