Question

After applying the correction for elevation and temperature, the runway length is 700 m.
The corrected runway length (in m) for an effective gradient of 1% is __________ (round off to the nearest integer).
 

• A. 840
• B. 700
• C. 720
• D. 740

Hint:

Remember: Runway length is increased by 20\% for every 1\% gradient as per ICAO or aviation design guidelines.

Answer 1

The Correct Option is A

Given: Corrected runway length after applying elevation and temperature corrections: \[ l = 700 { m},\quad {Gradient} = 1\% \] According to standards, for every 1% gradient, the runway length increases by 20%. \[ {Correction} = 700 \times \frac{20}{100} = 140 \] \[ {Corrected length} = 700 + 140 = 840 { m} \] \[ {Or simply: } 700 \times 1.2 = 840 { m} \] Hence, the final corrected length is \( \boxed{840 { m}} \).