AD and BC are equal perpendiculars to a line segment AB (see Fig). Show that CD bisects AB.
In ∆BOC and ∆AOD,
∠BOC = ∠AOD (Vertically opposite angles)
∠CBO = ∠DAO (Each 90º)
BC = AD (Given)
∴ ∆BOC ≅∆AOD (AAS congruence rule)
∴ BO = AO (By CPCT)
⇒ CD bisects AB.
In Fig. 9.26, A, B, C and D are four points on a circle. AC and BD intersect at a point E such that ∠ BEC = 130° and ∠ ECD = 20°. Find ∠ BAC.