For the capacity of cistern Take LCM of 5,6 = 30
Efficiency to fill the cistern = \(\frac{30}{5}\) \(\frac{units}{hr}\)
= 6 \(\frac{units}{hr}\)
Assume the efficiency of leak = \(- x \frac{units}{hr}\)
From the question, \((6 - x) × 6 = 30\)
\(6 - x = 5\)
\(x = 1 \)
From above, time taken by leak to empty it = \(\frac{30}{1} hrs\)
The correct option is (C): 30 hrs