Question

According to Bohr?s theory, the angular momentum for an electron of $3rd$ orbit is

• A. $3 \hbar$
• B. $1.5 \hbar$
• C. $9 \hbar$
• D. $2\frac{\hbar}{\pi}$

Answer 1

The Correct Option is A

Angular momentum, mvr
$ = \frac{nh}{2\pi} = \frac{3 \times h}{2 \pi} = \frac{1.5\, h }{\pi} $
$ = 3\hbar \left[ \because \hbar = \frac{h }{2 \pi}\right]$