Question:

Acceleration of the freely falling metal rod in a cycling ring?

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For freely falling objects near Earth's surface, the acceleration is always \( g \), which is approximately \( 9.8 \, \text{m/s}^2 \).
Updated On: Apr 25, 2025
  • \( g \)
  • \( 2g \)
  • \( 0 \)
  • \( g/2 \)
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The Correct Option is A

Solution and Explanation


When a metal rod is freely falling in a cycling ring, it experiences an acceleration equal to the acceleration due to gravity, \( g \). Since the rod is under the influence of gravity only, the force acting on it is the gravitational force, and hence the acceleration of the rod is \( g \), which is the acceleration due to gravity. Thus, the acceleration of the freely falling metal rod is \( g \).
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