Area of \(\triangle ABC=\frac{1}{2}\times Base \times Height\)
\(=\frac{1}{2}\times BC\times AD\)
\(\frac{1}{2}\times 9\times 6=27\;cm^2\)
Area of \(\triangle ABC = \frac{1}{2}\times AB\times CE\)
\(27=\frac{1}{2}\times7.5\times CE\)
\(CE =7.2\;cm\)
In triangle \( PQR \), the lengths of \( PT \) and \( TR \) are in the ratio \( 3:2 \). ST is parallel to QR. Two semicircles are drawn with \( PS \) and \( PQ \) as diameters, as shown in the figure. Which one of the following statements is true about the shaded area \( PQS \)? (Note: The figure shown is representative.)