Question:

∆ABC is isosceles with AB = AC = 7.5 cm and BC = 9 cm (Fig 9.17). The height AD from A to BC, is 6 cm. Find the area of ∆ABC. What will be the height from C to AB i.e., CE?
triangle ABC

Updated On: Oct 19, 2024
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Solution and Explanation

Area of ABC=12×Base×Height\triangle ABC=\frac{1}{2}\times Base \times Height

=12×BC×AD=\frac{1}{2}\times BC\times AD

12×9×6=27  cm2\frac{1}{2}\times 9\times 6=27\;cm^2

Area of ABC=12×AB×CE\triangle ABC = \frac{1}{2}\times AB\times CE

27=12×7.5×CE27=\frac{1}{2}\times7.5\times CE

CE=7.2  cmCE =7.2\;cm

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