The given wave equation is \( y = 0.02 \sin [30t - 4.0x] \) m.
To find the speed of the wave, we use the general form of the wave equation: \( y = A \sin ( \omega t - kx ) \), where:
From the given equation:
Substitute these values into the formula for wave speed:
\( v = \frac{30}{4.0} = 7.5 \, \text{m/s} \)
Thus, the speed of the wave is 7.5 m/s.
A particle is subjected to simple harmonic motions as: $ x_1 = \sqrt{7} \sin 5t \, \text{cm} $ $ x_2 = 2 \sqrt{7} \sin \left( 5t + \frac{\pi}{3} \right) \, \text{cm} $ where $ x $ is displacement and $ t $ is time in seconds. The maximum acceleration of the particle is $ x \times 10^{-2} \, \text{m/s}^2 $. The value of $ x $ is:
Two simple pendulums having lengths $l_{1}$ and $l_{2}$ with negligible string mass undergo angular displacements $\theta_{1}$ and $\theta_{2}$, from their mean positions, respectively. If the angular accelerations of both pendulums are same, then which expression is correct?