Question:

A water drop is divided into $8$ equal droplets. The pressure difference between the inner and outer side of the big drop will be

Updated On: Jun 20, 2022
  • same as for smaller droplet
  • $\frac{1}{2}$ of that for smaller droplet
  • $\frac{1}{4}$ of that for smaller droplet
  • twice that for smaller droplet
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The Correct Option is B

Solution and Explanation

Volume of big drop $=$ Volume of $8$ droplets ie,
$\frac{4}{3} \pi R^{3}=8 \times \frac{4}{3} \pi r^{3} $
$\therefore r=\frac{R}{2}$
For smaller drop,
$\Delta P_{s}=\frac{2 T}{r}=\frac{2 T}{R / 2}=\frac{4 T}{R}$
For bigger drop,
$\Delta P_{b}=\frac{2 T}{R}=\frac{1}{2} \Delta P_{s}$
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Surface Tension and Viscosity:

The surface tension of a liquid is all the time a function of the solid or fluid with which the liquid is in contact. If a value for surface tension is provided in a table for oil, water, mercury, or whatever, and the contacting fluid is unspecified, it is safe to consider that the contacting fluid is air.