Comprehension

A wall mounted lamp, made of fabric, is shown below. Lamp has cuboidal shape, open from top and bottom. A spherical bulb of diameter 7 cm is latched with a very thin rod. (Ignore the rod while making calculations.) Dimensions of the cuboid are 24 cm × 12 cm × 17 cm.

Question: 1

Find the surface area of the bulb.

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Using the diameter directly in the formula \(\pi d^{2}\) is faster than converting to radius for spheres when the diameter is a multiple of 7.
Updated On: Feb 20, 2026
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Solution and Explanation

Step 1: Understanding the Concept:
The bulb is spherical in shape. We need to find its total surface area using its diameter.
Step 2: Key Formula or Approach:
Surface area of a sphere:
\[ \text{SA} = 4\pi r^{2} \text{ or } \pi d^{2} \]
Step 3: Detailed Explanation:
Given: Diameter \(d = 7\) cm.
Radius \(r = \frac{d}{2} = 3.5\) cm.
Using \(\pi = \frac{22}{7}\):
\[ \text{SA} = 4 \times \frac{22}{7} \times 3.5 \times 3.5 \]
\[ \text{SA} = 4 \times \frac{22}{7} \times \frac{7}{2} \times \frac{7}{2} \]
\[ \text{SA} = \frac{4 \times 22 \times 49}{7 \times 4} = 22 \times 7 = 154 \text{ cm}^{2} \]
Step 4: Final Answer:
The surface area of the bulb is 154 \(\text{cm}^{2}\).
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Question: 2

What could be the maximum diameter of the bulb if at least 1 cm space is left from each side ?

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When fitting an object inside another, the smallest dimension of the container usually determines the maximum size of the object.
Updated On: Feb 20, 2026
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Solution and Explanation

Step 1: Understanding the Concept:
To fit inside the cuboidal space with a specific gap on all sides, the diameter must be less than the dimensions of the cuboid minus the required gaps.
Step 2: Detailed Explanation:
The cuboid dimensions are: Length \(L = 24\) cm, Width \(W = 12\) cm, Height \(H = 17\) cm.
A gap of 1 cm must be left from each side. This means for each dimension, we lose \(1 + 1 = 2\) cm of available space.
1. Along the width: Max diameter \(\le 12 - 2 = 10\) cm.
2. Along the length: Max diameter \(\le 24 - 2 = 22\) cm.
3. Along the height: The bulb can be anywhere, but it's restricted by the narrower sides of the box.
The most restrictive dimension is the width (12 cm).
Thus, the maximum diameter possible is \(12 - 2 = 10\) cm.
Step 3: Final Answer:
The maximum diameter of the bulb is 10 cm.
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Question: 3

Find the area of the fabric used if there is a fold of 2 cm on top and bottom edges.

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For open-ended prisms or cuboids, the material area is always the product of the base perimeter and the total material height.
Updated On: Feb 20, 2026
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Solution and Explanation

Step 1: Understanding the Concept:
The lamp is cuboidal but open at the top and bottom. The area of fabric used is the lateral surface area of the cuboid. The folds mean the actual height of fabric cut is more than the height of the lamp.
Step 2: Detailed Explanation:
Dimensions of cuboid: \(24\) cm \(\times 12\) cm \(\times 17\) cm.
Perimeter of the base \(= 2 \times (24 + 12) = 2 \times 36 = 72\) cm.
The height of the lamp is 17 cm.
Since there is a fold of 2 cm on the top edge and a fold of 2 cm on the bottom edge, the total height of the fabric required is:
\[ \text{Fabric Height} = 17 + 2 + 2 = 21 \text{ cm} \]
Area of fabric \(= \text{Perimeter} \times \text{Fabric Height} \)
\[ \text{Area} = 72 \times 21 = 1512 \text{ cm}^{2} \]
Step 3: Final Answer:
The area of the fabric used is 1512 \(\text{cm}^{2}\).
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Question: 4

Find the space available inside the lamp.

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Space available is synonymous with the internal volume of the shape.
Updated On: Feb 20, 2026
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Solution and Explanation

Step 1: Understanding the Concept:
The space available inside the lamp refers to the volume enclosed by the cuboidal fabric frame.
Step 2: Key Formula or Approach:
Volume of a cuboid:
\[ V = L \times W \times H \]
Step 3: Detailed Explanation:
The dimensions of the cuboidal frame are:
Length \(L = 24\) cm
Width \(W = 12\) cm
Height \(H = 17\) cm
\[ \text{Volume} = 24 \times 12 \times 17 \]
\[ \text{Volume} = 288 \times 17 = 4896 \text{ cm}^{3} \]
Step 4: Final Answer:
The space available inside the lamp is 4896 \(\text{cm}^{3}\).
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