Step 1: Set up the initial conditions.
Let the total mixture be 95 litres with milk and water in the ratio 15:4. Therefore, the amount of milk is:
\[ \text{Milk} = \frac{15}{19} \times 95 = 75 \, \text{litres}. \] The amount of water is:
\[ \text{Water} = \frac{4}{19} \times 95 = 20 \, \text{litres}. \]
Step 2: Remove P litres of the mixture.
When P litres of the mixture is removed, the amounts of milk and water removed are in the same ratio (15:4). Hence, the amount of milk removed is:
\[ \text{Milk removed} = \frac{15}{19} \times P, \text{Water removed} = \frac{4}{19} \times P. \]
Step 3: Add 18 litres of water.
After removing P litres of the mixture, 18 litres of water is added to the remaining mixture. So, the new amount of water becomes:
\[ \text{New water} = 20 - \frac{4}{19} \times P + 18. \]
Step 4: Set up the new ratio.
We are told that the new ratio of milk to water becomes 3:2. So, we set up the equation:
\[ \frac{75 - \frac{15}{19} \times P}{20 - \frac{4}{19} \times P + 18} = \frac{3}{2}. \]
Step 5: Solve for P.
Simplifying the equation:
\[ \frac{75 - \frac{15}{19} \times P}{38 - \frac{4}{19} \times P} = \frac{3}{2} \Rightarrow 2 \times (75 - \frac{15}{19} \times P) = 3 \times (38 - \frac{4}{19} \times P). \] Expanding both sides:
\[ 150 - \frac{30}{19} \times P = 114 - \frac{12}{19} \times P. \] Simplifying:
\[ 150 - 114 = \frac{30}{19} \times P - \frac{12}{19} \times P \Rightarrow 36 = \frac{18}{19} \times P. \] Solving for P:
\[ P = \frac{36 \times 19}{18} = 38. \]
Step 6: Conclusion.
Thus, the value of P is 38 litres, and the correct answer is (d).
Statement: All flowers are beautiful. Some beautiful things are fragile.
Conclusion I: Some flowers are fragile.
Conclusion II: All beautiful things are flowers.
Statements: All apples are fruits. All fruits are tasty.
Conclusions: 1. All apples are tasty. 2. Some tasty things are apples.
What is the next number in each of the following 3 sequences?
8, 17, 33, 67, 133, 1?