A unit positive charge is moved from point A to point B by a distance of 20 cm, on an equipotential surface as shown in the figure. The work done to move this charge is:

In this case, the charge is moved along an equipotential surface.
By definition, an equipotential surface is a surface where the potential difference between any two points on the surface is zero.
As a result, no work is required to move a charge between any two points on an equipotential surface. Therefore, the work done is zero: \[ W = q \cdot \Delta V \] Since \( \Delta V = 0 \) on the equipotential surface: \[ W = q \cdot 0 = 0 \, {J} \] Thus, the work done to move the charge is \( 0 \, {J} \).
Match List-I with List-II:
| List-I (Modulation Schemes) | List-II (Wave Expressions) |
|---|---|
| (A) Amplitude Modulation | (I) \( x(t) = A\cos(\omega_c t + k m(t)) \) |
| (B) Phase Modulation | (II) \( x(t) = A\cos(\omega_c t + k \int m(t)dt) \) |
| (C) Frequency Modulation | (III) \( x(t) = A + m(t)\cos(\omega_c t) \) |
| (D) DSB-SC Modulation | (IV) \( x(t) = m(t)\cos(\omega_c t) \) |
Choose the correct answer:
