Question:

A tunnel is dug along a diameter of the earth. The force on a particle of mass 'm' placed in the tunnel at a distance X from the center is

Updated On: Jul 6, 2022
  • $\frac{GM_em}{R^3}x$
  • $\frac{GM_em}{R^2}x$
  • $\frac{GM_em}{R^3x}$
  • $\frac{GM_emR^3}{x}$
Hide Solution
collegedunia
Verified By Collegedunia

The Correct Option is A

Solution and Explanation

$F = \frac{GM'm}{x^2} $ but $\frac{M'}{x'} = \frac{M}{R'}$
Was this answer helpful?
0
0

Top Questions on Gravitation

View More Questions

Concepts Used:

Gravitation

In mechanics, the universal force of attraction acting between all matter is known as Gravity, also called gravitation, . It is the weakest known force in nature.

Newton’s Law of Gravitation

According to Newton’s law of gravitation, “Every particle in the universe attracts every other particle with a force whose magnitude is,

  • F ∝ (M1M2) . . . . (1)
  • (F ∝ 1/r2) . . . . (2)

On combining equations (1) and (2) we get,

F ∝ M1M2/r2

F = G × [M1M2]/r2 . . . . (7)

Or, f(r) = GM1M2/r2

The dimension formula of G is [M-1L3T-2].