Let the length of the first train be \( L \). The relative speed of the two trains is \( 48 + 42 = 90 \, \text{km/h} \).
Converting this to meters per second, we get \( 90 \times \frac{5}{18} = 25 \, \text{m/s} \).
The total distance covered when the two trains cross each other is \( L + \frac{L}{2} = \frac{3L}{2} \).
Since the time taken is 12 seconds, \( \frac{3L}{2} = 25 \times 12 \), so \( L = 200 \, \text{meters} \).
The length of the platform is then \( \frac{200}{45} \times 1000 = 400 \, \text{meters} \).
Store | Respective ratio of number of linen kurtis to cotton kurtis sold |
A | 7:5 |
B | 5:6 |
C | 3:2 |
D | 5:3 |
E | 4:3 |
F | 7:3 |
Store | Respective ratio of number of linen kurtis to cotton kurtis sold |
A | 7:5 |
B | 5:6 |
C | 3:2 |
D | 5:3 |
E | 4:3 |
F | 7:3 |