Let the length of the train be \(L\) meters.
The train is running at 80 km/h, which is \(80 \times \frac{1000}{3600} = \frac{800}{36} = \frac{200}{9}\) m/s.
The train crosses a 350 m long tunnel in 36 seconds.
The total distance the train covers is the length of the train plus the length of the tunnel: \(L + 350\) meters.
Distance = Speed × Time, so \(L + 350 = \frac{200}{9} \times 36 = 200 \times 4 = 800\).
\(L = 800 - 350 = 450\) meters.
The speed of the train is 80 km/h, which is converted to meters per second as $80 \times \frac{1000}{3600} = 22.22$ m/s.
The total distance covered by the train in 36 seconds is $22.22 \times 36 = 800$ meters.
The length of the train is $800 - 350 = 450$ meters.
List-I | List-II | ||
A | Megaliths | (I) | Decipherment of Brahmi and Kharoshti |
B | James Princep | (II) | Emerged in first millennium BCE |
C | Piyadassi | (III) | Means pleasant to behold |
D | Epigraphy | (IV) | Study of inscriptions |