Question

A train after travelling 150 km meets with an accident and then proceeds at \(\frac{3}{5}\) of its former speed and arrives at its destination 8 hours late. Had the accident occurred 360 km further, it would have reached the destination 4 hours late. What is the total distance travelled by the train ?

• A. 960 km
• B. 870 km
• C. 840 km
• D. 1100 km

Answer 1

The Correct Option is B

Assume the speed of the train be v km/hr and the total distance travelled by the train be d kms and the time taken to reach the destination if no accident occured is t hours.

\(\frac{150}{v}\) + d-\(\frac{150}{0.6v}\) = t + 8  — Equation 1

\(\frac{510}{v}\) + d-\(\frac{510}{0.6v}\) = t + 4  — Equation 2

After solving the above equations, we get: 
After subtracting the equation 1 from equation 2 we get,
 d = 870 kms
The correct option is (B)