Question:

A train 130 meters long crosses a platform in 30 seconds with a speed of 45 km/h. Then the length of the platform is?

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Convert all units before calculating and use total distance = train length + platform length.
  • 270 m
  • 245 m
  • 280 m
  • 296 m
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The Correct Option is B

Solution and Explanation

Step 1: Convert speed into m/s.
\[ 45 \text{ km/h} = \frac{45 \times 1000}{3600} = 12.5 \text{ m/s} \] Step 2: Use formula for distance covered when crossing a platform:
\[ \text{Distance} = \text{Speed} \times \text{Time} \] \[ = 12.5 \times 30 = 375 \text{ meters} \] Step 3: Distance covered = length of train + length of platform
Let length of platform = \(x\). Then,
\[ 130 + x = 375 \] \[ x = 375 - 130 = 245 \text{ meters} \] Hence, length of the platform is \(\boxed{245 \text{ m}}\).
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