Question:

A thin circular disk of radius $R$ is uniformly charged with density $\sigma$ > 0 per unit area. The disk rotates about its axis with a uniform angular speed $\omega$. The magnetic moment of the disk is :

Updated On: Jul 31, 2023
  • $\pi R^{4}\sigma\omega$
  • $\frac{\pi R^{4}}{2}\sigma\omega$
  • $\frac{\pi R^{4}}{4}\sigma\omega$
  • $2\pi R^{4}\sigma\omega$
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The Correct Option is C

Solution and Explanation

$\frac{q}{2M} = \frac{Magnetic \,dipole \,moment}{Angular \,momentum}$ $\therefore\quad$ Magnetic dipole moment (M) $M = \frac{q}{2M}. \left(\frac{MR^{2}}{2}\right)\omega$ $= \frac{1}{4}\sigma.\pi R^{4}\omega$

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Magnets are used in many devices like electric bells, telephones, radio, loudspeakers, motors, fans, screwdrivers, lifting heavy iron loads, super-fast trains, especially in foreign countries, refrigerators, etc.

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Some of the properties of the magnetic field lines are:

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