Question

A tap can fill a tank in 6 hours. After half the tank is filled, three more similar taps are opened. What is the total time taken to fill the tank completely?

• A. 3 hours 15 min
• B. 3 hours 45 min
• C. 3 hours 40 min
• D. 3 hours 50 min

Hint:

Break the work at the switching point. Compute time for each phase using \(\text{time}=\frac{\text{work}}{\text{rate}}\) and add them.

Answer 1

The Correct Option is B

Step 1: Write the single–tap rate.
One tap fills the tank in 6 hours \(\Rightarrow\) rate \(=\frac{1}{6}\) tank/hour. Step 2: Time to fill the first half with one tap.
\[ t_1=\frac{\text{work}}{\text{rate}}=\frac{\frac12}{\frac16}=3\ \text{hours}. \] Step 3: Fill the remaining half with 4 taps (1 existing + 3 new).
Combined rate \(=4\times\frac{1}{6}=\frac{2}{3}\) tank/hour.
\[ t_2=\frac{\frac12}{\frac{2}{3}}=\frac{1}{2}\times\frac{3}{2}=\frac{3}{4}\ \text{hour}=45\ \text{minutes}. \] Step 4: Total time.
\[ t_{\text{total}} = t_1+t_2 = 3\ \text{hours}+45\ \text{minutes}=3\ \text{hours }45\ \text{minutes}. \] \[ \boxed{3\ \text{hours }45\ \text{minutes}} \]