Question

A syringe is used to exert 1.5 atmospheric pressure to release water horizontally. The speed of water immediately after ejection is .............. m s$^{-1}$. (Take 1 atmospheric pressure = $10^5$ Pa, density of water = $10^3$ kg m$^{-3}$.) (Specify your answer in m s$^{-1}$ as an integer.)
 

Hint:

When pressure drives a fluid, the exit speed depends only on $\Delta P$ and density.

Answer 1

Correct Answer: 0.45

Step 1: Use Bernoulli's equation for fluid exit velocity.
The exit speed from a pressurized container is given by
$v = \sqrt{\frac{2\Delta P}{\rho}}$.

Step 2: Compute pressure difference.
$\Delta P = 1.5 \times 10^5$ Pa.

Step 3: Substitute values.
$v = \sqrt{\frac{2(1.5\times10^5)}{10^3}} = \sqrt{300}$.

Step 4: Final value.
$\sqrt{300} \approx 17.3$, so the answer is $17$ m/s (integer).