Question

A stream of 200 L s$^{-1}$ is diverted from a canal to irrigate a wheat field in 8 hours. If the runoff from the field is 500 m$^3$ and the conveyance efficiency is 75%, the application efficiency in percent is _____.

Hint:

Application efficiency measures how effectively water applied to a field is utilized, calculated as the ratio of runoff to the water received by the field.

Answer 1

Correct Answer: 88.4

First, calculate the total water available for irrigation in 8 hours:
\[ \text{Total water diverted} = 200 \, \text{L/s} \times 3600 \, \text{s/h} \times 8 \, \text{h} = 200 \times 28800 = 5760000 \, \text{L} = 5760 \, \text{m}^3. \] Next, account for the conveyance efficiency:
\[ \text{Water received by the field} = 5760 \times 0.75 = 4320 \, \text{m}^3. \] The application efficiency is the ratio of runoff to the water received by the field:
\[ \text{Application efficiency} = \frac{500}{4320} \times 100 = 11.57%. \] Thus, the application efficiency is approximately \(\boxed{11.57}%\).