A stone is thrown vertically up from the top end of a window of height 1.8 m with a velocity of 8 m/s\(^1\). The time taken by the stone to cross the window during its downward journey is:
(Acceleration due to gravity \( g = 10 \) ms\(^{-2}\))
Show Hint
Use kinematic equations to solve free-fall problems.
- Time is always positive in motion calculations.
Step 1: Use kinematic equation
Using the equation of motion:
\[
h = ut + \frac{1}{2} g t^2.
\]
Substituting \( h = 1.8 \), \( u = 8 \), and \( g = 10 \):
\[
1.8 = 8t + \frac{1}{2} (10) t^2.
\]
Step 2: Solve for \( t \)
Rearrange:
\[
1.8 = 8t + 5t^2.
\]
Solving for \( t \), we get \( t = 0.2 \) s.
Thus, the correct answer is \( \boxed{0.2} \) s.